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5v^2-30v-70=0
a = 5; b = -30; c = -70;
Δ = b2-4ac
Δ = -302-4·5·(-70)
Δ = 2300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2300}=\sqrt{100*23}=\sqrt{100}*\sqrt{23}=10\sqrt{23}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-10\sqrt{23}}{2*5}=\frac{30-10\sqrt{23}}{10} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+10\sqrt{23}}{2*5}=\frac{30+10\sqrt{23}}{10} $
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